Question

(x^a+b)^a-b . (x^b+c)^b-c . (x^c+a)^c-a

Please Answer This ASAP​

Answer 1

The answer is 1.

Step-by-step explanation:

(x^a+b)^a-b . (x^b+c)^b-c . (x^c+a)^c-a

x^a²–b² × x^b²–c²× x^c²–a²

x^a²–b²+(b²–c²)+(c²–a²)

x^a²–b²+b²–c²+c²–a²

x⁰. [anything to the power 0 is 1 so x⁰ is 1]

1

Answer 2

$\huge \underline \bold \red{correct \: question}$

(x^a/x^-b)^a-b*(x^b/x^-c)^b-c*(x^c/x^-a)^c-a

$\huge \mathtt \red {a} \pink{n} \blue{s} \pink{w} \blue{e} \pink{r}$

(Xa/x-b)a-b . (xb/x-c)b-c .(xc/x-a)c-a

= (xa+b)a-b , (xb+c)b-c .(xc+a)c-a

= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)

= xo

= 1 = R.H.S.