Math, asked by abhrajyoti1, 1 month ago

x-a/b-a+x-c/b-c=2 then x=?​

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Answered by ITZURADITYAKING
1

Answer:

Given,

Given,(xbxa)a2+ab+b2×(xcxb)b2+bc+c2×(xaxc)c2+ca+a2

Given,(xbxa)a2+ab+b2×(xcxb)b2+bc+c2×(xaxc)c2+ca+a2=(xa−b)a2+ab+b2×(xb−c)b2+bc+c2×(xc−a)c2+ca+a2

Given,(xbxa)a2+ab+b2×(xcxb)b2+bc+c2×(xaxc)c2+ca+a2=(xa−b)a2+ab+b2×(xb−c)b2+bc+c2×(xc−a)c2+ca+a2=xa3+a2b+ab2−a2b−ab2−b3×xb3+b2c+bc2−cb2−bc2−c3×x

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