x^a(b-c)/x^b(a-c) ÷(x^b/x^a)^c= 1
pls ans. fast i'll mark brainliest
Answers
Answered by
0
Step-by-step explanation:
x^(ab-bc-ab+bc-bc+ac)=1
x^c(a-b)=1
so c(a-b)=0
a=b
(when x,c≠0)
I hope this helps
Answered by
0
x^a(b-c)/x^b(a-c) ÷(x^b/x^a)^c
(x^ab-ac/x^ab-bc) ÷(x^bc/x^ac)
x^ab-ac-ab+bc ÷ x^bc-ac
x^-ac+bc-bc+ac
x^0
1 = RHS
Mark me brainliest if you like my answer.
Note that I have changed the sign because
x^a÷x^b =x^a-b.
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