Math, asked by noncopyrightACCOUNT, 10 months ago

x^a(b-c)/x^b(a-c) ÷(x^b/x^a)^c= 1


pls ans. fast i'll mark brainliest ​

Answers

Answered by BrotishPal
0

Step-by-step explanation:

x^(ab-bc-ab+bc-bc+ac)=1

x^c(a-b)=1

so c(a-b)=0

a=b

(when x,c≠0)

I hope this helps

Answered by saikharpandey3127
0

x^a(b-c)/x^b(a-c) ÷(x^b/x^a)^c

(x^ab-ac/x^ab-bc) ÷(x^bc/x^ac)

x^ab-ac-ab+bc ÷ x^bc-ac

x^-ac+bc-bc+ac

x^0

1 = RHS

Mark me brainliest if you like my answer.

Note that I have changed the sign because

x^a÷x^b =x^a-b.

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