x^a(b-c)/x^b(a-c) ÷ (x^b/x^a)^c
rita01:
its proof this answer should be = to 1
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Hi frnd.........
LHS = x^ab-ac/x^ab-bc × (x^a/x^b)^c
x^ab-ac/x^ab-bc × x^ac/x^bc
x^ab-ac+ac/x^ab-bc+bc
(-ac+ac gets cancelled) (-bc+bc gets cancelled)
x^ab/x^ab (ab gets cancelled )
= 1= RHS
∴it is proved
hope it helps..........:D
LHS = x^ab-ac/x^ab-bc × (x^a/x^b)^c
x^ab-ac/x^ab-bc × x^ac/x^bc
x^ab-ac+ac/x^ab-bc+bc
(-ac+ac gets cancelled) (-bc+bc gets cancelled)
x^ab/x^ab (ab gets cancelled )
= 1= RHS
∴it is proved
hope it helps..........:D
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