Math, asked by pk030833, 9 months ago

(x^a)^b-c*(x^b)^c-a*(x^c)^a-b=1 . please solve this question and I will mark you the brainliest

Answers

Answered by sdmunswer
0

Answer:

the ans is

Step-by-step explanation:

(x^a)^b-c*(x^b)^c-a*(x^c)^a-b=1

(x^a)^b-c*(x^b)^c-a*(x^c)^a-b

(x^a)^b-c*(x^b)^c-a*(x^c)^a-b

(x^a)^b-c*(x^b)^c-a*(a-b

x^a)^b-c*(x^b*(a-b

a-b=1

Similar questions