Question

((x ^ (a + b))/(x ^ c)) ^ (a - b) * ((x ^ (b + c))/(x ^ a)) ^ (b - c) * ((x ^ (c + a))/(x ^ b)) ^ (c - a) = 1​

Answer 1

We need to prove the gives equation is unity that si 1

LHS=(xa/xb)^1/ab( xb /xc)^1/bc(xc/xa)1/ca

Using laws of exponents

= (xa/xb)1/ab( xb /xc)1/bc(xc/xa)1/ca

= x(a-b)/ab * x^(b-c)/bc * x^(c-a)/ca

= x[(a-b)/ab + (b-c)/bc + (c-a)/ca]

= x[c(a-b)/abc + a(b-c)/abc + b(c-a)/abc ]

= x { [c(a-b)+ a(b-c) + b(c-a) ]/abc }

= x ( ac – bc + ab – ac + bc – ab ] /abc

= x 0/abc

HENCE PROVED X^0= 1

PLS MARK AS BRAINLIEST AND 1 THANKS FOR HELP

Answer 2

solution answer comes 1