Math, asked by WildPawGaming, 4 months ago

x^a-b y^c-d/x^2b-a y^c

Answers

Answered by Higuys39498

0

x^a-b y^c-d/x^2b-a y^c

= x^a-b-2b-a × y^c-d-c

=x^-3b × y^-d

= 1

___________

x^3b × y^d

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