x = a cos 0, y = a sin 0 is a parametric
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Given, x=acosθ and y=asinθ
After eliminating the parameter the circle is x
2
+y
2
=a
2
which have center (0,0) and radius a
Since ∠OQP=∠QRP=
2
π
, the circle on OP as diameter is the circumcised of ΔPQR
∴ its equation is (x−0)(x−h)+(y−0)(y−k)=0
⇒x
2
+y
2
−hx−ky=0
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