Question

x = a cos A and  y = b sin A,Then find    b²x² + a²y²​

Answer 1

Answer:

a^2b^2

Step-by-step explanation:

x= a cosA__eq 1

y= b sinA__eq 2

eq 1*b => bx= ab cosA

Squaring on both sides

b^2x^2= a^2b^2 cos^2 A__eq 3

eq 2*a=> ay= ab sinA

Squaring on both sides

a^2y^2= a^2b^2 sin^2 A__eq 4

eq 3+eq 4=> b^2x^2+a^2y^2= a^2b^2(cos^2 A+ sin^2 A)

= a^2b^2