Math, asked by shernameenu, 7 months ago

x=a(cos t+sin t ),y=a(sin t-cos t).dy/dx?​

Answers

Answered by bagkakali
2

Answer:

x=a(cost+sint)

dx/dt=a(-sin t+cost)

y=a(sint-cos t)

dy/dt=a(cos t+sin t)

dy/dx=dy/dt.dt/dx

=a(sin t +cos t)/a(cos t -sin t)

=(cos t+sin t)/(cos t -sin t)

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