Question

X = a (cos t + tsint) and y= a (sin t - tcost) find dy/dx

Answer 1

dy/dx=dy/dt÷dx/dt

dx/dt=a(-sint+tcost+sint)

dx/dt=a(tcost). -1

dy/dt=a(cost+tsint-cost)

dy/dt=a(tsint)

dy/dx=atsint/at cost

dy/dx=Tant
Answer.

Answer 2

⭐hey there!!

=> x = a(cost + tsint)

=> dx/dt = a(-sint + sint + tcost) = atcost ----------(1)

Again,

=>> y = a(sint - tcost)

=> dy/dt = a(cost -cost +tsint) = atsint ----------(2)


Now dy/dx = dy/dt ÷dx/dt :

So dividing eqn (2) by (1)/

=>>> dy/dx = atsint/atcost = tant.

Therefore, dy/dx = tant

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⭐hope it will help u