Math, asked by Lokeshwarreddy, 1 year ago

x =a cosec theta, y=b cot theta then b2x2-a2y2=?

Answers

Answered by singhbhupendrap6ux6y

0

b2x2-a2y2=b2×a2cosec^2-a^2b^2cot^2
b^2a^2(cosec^2-cot^2)
b^2 × a ^2 × 1

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