x-a is a factor of p(x)= ax^2+bx+c. Which of the following is true?
A.
p(a)=2
B.
p(a) = 0
C.
p(2)=1
D.
p(b)=0
Answers
Answered by
12
p(a)=0
Answer. B.p(a) = 0
See if g(x) = x- a
Then g(x) is a factor of p(x)
The zero of polynomial = a
Therefore p(a)= 0
I hope this helps
◀POLYNOMIAL▶
@sid000 #!!
Answer. B.p(a) = 0
See if g(x) = x- a
Then g(x) is a factor of p(x)
The zero of polynomial = a
Therefore p(a)= 0
I hope this helps
◀POLYNOMIAL▶
@sid000 #!!
Answered by
14
HELLO DEAR,
If P(x) be a polynomial and it is divided by another polynomial (x - a), then the quotient is represented by Q(x) and the remainder is given by R(x). Then remainder theorem says that -
P(x) = (x - a) Q(x) + R(x)
Factor theorem is a special case of remainder
theorem.
It states that if a polynomial P(x) is evenly
divided by another polynomial (x - a),
then it leaves no remainder; i.e. R(x) = 0 and
hence (x - a) is said to be the factor of P(x).
According to factor theorem -
P(x) = (x - a) Q(x)
In other words, (x - a) is said to be the factor of polynomial P(x); if P(a) = 0.
I HOPE ITS HELP YOU DEAR,
THANKS
If P(x) be a polynomial and it is divided by another polynomial (x - a), then the quotient is represented by Q(x) and the remainder is given by R(x). Then remainder theorem says that -
P(x) = (x - a) Q(x) + R(x)
Factor theorem is a special case of remainder
theorem.
It states that if a polynomial P(x) is evenly
divided by another polynomial (x - a),
then it leaves no remainder; i.e. R(x) = 0 and
hence (x - a) is said to be the factor of P(x).
According to factor theorem -
P(x) = (x - a) Q(x)
In other words, (x - a) is said to be the factor of polynomial P(x); if P(a) = 0.
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
thanks for brainliest
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