Question

x = a sec thetha , y = b tan thetha then prove that x^2/a^2 - y^2/b^2

Answer 1

X=a sec thetha ,y=b tan thetha

X^2/a^2-y^2/b^2=

Put the value x and y

A^2sec^2thetha /a^2-b^2tan^2thetha/b^2

sec^2-tan^2 =1