Math, asked by Bhoomitisha, 6 months ago

x= a secø , y = b tanø , then b²x²-a²y² = ?

Answers

Answered by leenasingh12284

1

Step-by-step explanation:

Hope you will understand

Attachments:

Answered by sowjanyasrinivas2005

2

Answer:

b2a2

Step-by-step explanation:

=b2(a secø)2-a2(b tanø)2

=b2a2sec2ø-a2b2tan2ø

=b2a2(sec2ø-tan2ø). [sec2ø-tan2ø=1]

=b2a2

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