Question

x = a sin 0 and y=b cos 0, write the value of (b^2 x^2 + a^2 y^2)​

Answer 1

Answer:

a^2b^2

I hope this will help.

Answer 2

Answer:

Step-by-step explanation:

b^2 × x^2 + a^2 × y^2

=b^2 × a sin^2theta + a^2 × b^2 cos^2theta

=b^2 × a^2 × (cos^2theta + sin^2theta)

=b^2 × a^2 × 1

=a^2 × b^2

Thank you

Hope it helped you