Question

(x^a/x^b)^(a+b-c) * (x^b/x^c)^(b+c-a) * (x^c/x^a)^(c+a-b) = 1 . Prove the Sum answer it​

Answer 1

Answer:

the math problem is so easy

Answer 2

Step-by-step explanation:

${\frac{ {x}^{a} }{ {x}^{b} }}^{(a + b - c)} \times { \frac{ {x}^{b} }{ {x}^{c} } }^{(b + c - a)} \times { \frac{ {x}^{c} }{ {x}^{a} } }^{(c + a - b)} \\ = {x}^{ {(a - b)}^{ \:{(a + b - c ) }} } \times {x}^{ {(b - c)}^{{(b + c - a)}} } \times {x}^{ {(c - a)}^{c + a - b} } \\ = {x}^{(a - b)(a + b - c) +(b - c)(b + c - a) + (c - a)(c + a - b)} \\ = {x}^{ ({a}^{2} + ab - ac - ab - {b}^{2} + bc + {b}^{2} + bc - ab - bc - {c}^{2} + ac + {c}^{2} +ac - bc - ac - {a}^{2} + ab ) } \\ = {x}^{( {a}^{2} - {a}^{2} + {b}^{2} - {b}^{2} + {c}^{2} - {c}^{2} + ab + ab - ab - ab + bc + bc - bc - bc + ac + ac - ac - ac ) } \\ = {x}^{0} = 1$