Question

(x^a/x^b)^c ×(x^b/x^c)^a×(x^c/x^a)^b
find​

Answer 1

Answer:

1

Step-by-step explanation:

(x^ca/x^bc)×(x^ab/x^ca)×(x^bc/x^ab)

=x^ca-bc+ab-ca+bc-ab

=x^0

=1

Answer 2

x^ac-bc+ab-ac+bc-ab

x^0

1