Math, asked by aymen3, 7 months ago

(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0​

Answers

Answered by aiyshanizar792
1

Answer:

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Step-by-step explanation:

(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0

x²-ax-xb+ab+x²-bx+bc-cx+x²-ax+ac-cx=0

3x²-2ax-2bx-2cx+ab+bc+ca=o

3x²-2x(a+b+c)+ab+bc+ca=0

hope it is correct and helpful

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