(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0
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Step-by-step explanation:
(x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0
x²-ax-xb+ab+x²-bx+bc-cx+x²-ax+ac-cx=0
3x²-2ax-2bx-2cx+ab+bc+ca=o
3x²-2x(a+b+c)+ab+bc+ca=0
hope it is correct and helpful
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