(x+a) (x+b) (x+c)=
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(x + a)(x + b)(x + c) = (x + a){(x + b)(x + c)}
= (x + a){x2
2
+ (b + c)x + bc}
= x{x2
2
+ (b + c)x + bc} + a{x2
2
+ (b + c)x + bc}
= x3
3
+ (b + c)x2
2
+ bcx + ax2
2
+ a(b + c)x + abc
= x3
3
+ (a + b + c)x2
2
+ (bc + ab + ac)x + abc
= x3
3
+ (a + b + c)x2
2
+ (ab + bc + ca)x + abc
Therefore, (x + a)(x + b)(x + c) = x3
3
+ (Sum of the constant terms)x2
2
+ (Sum of the product of constant terms taking two at a time)x + Product of constant terms.
= (x + a){x2
2
+ (b + c)x + bc}
= x{x2
2
+ (b + c)x + bc} + a{x2
2
+ (b + c)x + bc}
= x3
3
+ (b + c)x2
2
+ bcx + ax2
2
+ a(b + c)x + abc
= x3
3
+ (a + b + c)x2
2
+ (bc + ab + ac)x + abc
= x3
3
+ (a + b + c)x2
2
+ (ab + bc + ca)x + abc
Therefore, (x + a)(x + b)(x + c) = x3
3
+ (Sum of the constant terms)x2
2
+ (Sum of the product of constant terms taking two at a time)x + Product of constant terms.
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