Math, asked by akgaming167, 7 months ago

(x-a)(x- b) = x² - (a – b)x + ab. (true or false)​

Answers

Answered by MagicalBeast
11

Answer:

false

Step-by-step explanation:

LHS = (x-a)(x-b) = (x)(x) +(x)(-b) + (-a)(x) + (-a)(-b)

= x² - ax -bx + ab

= x² - (a +b)x + ab

RHS = x² -(a-b)x +ab

LHS ≠ RHS

hence false

Answered by DivineEyes
26

 \sf \huge \blue {Question:-}

 \red{\sf ✧ \: State \: True \: or \: False}

 \red{\sf (x-a)(x- b) = x² - (a – b)x + ab}

________________________________

 \sf \huge \blue {Answer:-}

 \red{\sf ☞ \: False}

________________________________

 \sf \huge \blue {Explanation:-}

L.H.S = (x-a)(x-b)

= x(x-b) -a(x-b)

= x² - bx -ax + ab

= x² - (a+b)x + ab

⠀ ⠀⠀ ⠀ ⠀⠀ ⠀

R.H.S. = x² - (a - b)x + ab

⠀ ⠀⠀ ⠀ ⠀⠀ ⠀

 \red{\sf As, \: x² - (a+b)x + ab  ≠ x² - (a - b)x + ab}

 \red{\sf Therefore, \: L.H.S ≠ R.H.S}

⠀ ⠀⠀ ⠀ ⠀⠀ ⠀

 \red{\sf Therefore, \: the \: above \: equation \: is \:  wrong}

 \red{\sf and \: right \:  equation \: is }

 \red{\sf (x-a)(x-b) = x² - (a+b)x + ab}

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