(x+a)(X+b)= x2+(a+b)x+ab
verify it
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Answered by
2
Answer:
We have
(x + a) (x + b) = x2 + (a + b)x + ab
Putting a = 2, b =3 and x = 4, we have
LHS = (x + a) (x + b)
= (4 + 2) (4 +3)
= 6 x 7
= 42
RHS = x2 + (a + b)x + ab
= (4)2 + ( 2 +3)x + (2) x (3)
= 16 + 5 x 4 + 6
= 16 +26
= 42
i.e. LHS = RHS
Thus, the given identity is true for the given values.
Answered by
1
Answer:
( X+ a ) ( X+ b ) = X² + ( a + b ) X + ab
By multiplying
X( X+ b) + a ( X + b)
X² + Xb + aX + ab
X² ( a + b) X + ab ( By taking X as common )
X² + ( a + b ) X + ab = X² + ( a + b ) X + ab
Hence, Verified.
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