Question

√x+√a-x=√y+√a-y=√z+√a-z then proved that (y-z) (z-x) (x-y) =0​

Answer 1

Answer:

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Step-by-step explanation:

ax/y = ay/z = az/x = (x+y+z)

x/y = y/z = z/x = (x+y+z) /a

Suppose (x+y+z) /a =k

x= k*y

y= k*z

z= k*x

Add above three equations

(x+y+z) = (x+y+z)*k

Now put the value of k

(x+y+z) = (x+y+z) *(x+y+z) /a

Hence (x+y+z) = a