Question

X/a+y/b-a-b=0,x/a2+y/b2=-2=0

Answer 1

Step-by-step explanation:

X/a+Y/b= a+b

bX+aY= (a+b) ab.................(1)

X/a²+Y/b²= 2

b²X+a²Y= 2a²b².................(2)

(1) ×b - (2)

a(b-a)Y= (a+b)ab²- 2a²b²

Y= b²(a+b)/(b-a) - 2ab²/ (b-a)

= (ab²+b³-2ab²)/(b-a)

= (b³-ab²) / (b-a)

= b²

substituting. y= b² in (1)

bX+ab²= (a+b)ab

X= a(a+b) -ab= a²+ab-ab= a²

X= a²

Y=b²