Math, asked by 23himanshum, 7 months ago

x/a-y/b = a-b ; x/a2-y/b2= 0

Answers

Answered by sonisiddharth751
32

Answer:

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Answered by rishkrith123
1

Answer:

The values of x and y are a² and b² respectively

Step-by-step explanation:

Given,

\frac{x}{a} - \frac{y}{b} = a-b....(1), and

\frac{x}{a^2} - \frac{y}{b^2} = 0.....(2)

To find,

The value of x and y

Calculation,

From equation (2)

\frac{x}{a^2} - \frac{y}{b^2} = 0

\implies x=a^2 \times \frac{y}{b^2}....(3)

Substitute equation (3) in (1)

\frac{\frac{a^2y}{b^2} }{a} - \frac{y}{b} = a-b\\\implies \frac{ay}{b^2} -\frac{by}{b^2} = a-b\\\implies \frac{y}{b^2} (a-b) = a-b\\\implies y = b^2

Substituting y = b² in equation (3)

We get x = a² (b²/b²)

⇒ x = a²

Therefore, the values of x and y are a² and b² respectively.

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