Question

x/a+y/b=a+b; x/a2+y/b2=2

Answer 1

here is your answer i hope it will help u

Answer 2

$\frac{x}{a} + \frac{y}{b} = a + b \\ ay + bx = ab(a + b) \\ {a}^{2} y + abx = {a}^{2} b(a + b)$
$\frac{x}{ {a}^{2} } + \frac{y}{ {b}^{2} } = 2 \\ {a}^{2} y + {b}^{2} x = 2 {a}^{2} {b}^{2}$
Now subtracting the two equations, we get
$abx - {b}^{2} x = {a}^{2} b(a + b - 2b) \\ x(ab - {b}^{2} ) = {a}^{2} b(a - b) \\ x = \frac{ {a}^{2}b(a - b) }{b(a - b)} \\ x = {a}^{2}$
Similarly you can solve for y, which would give
$y = {b}^{2}$