x/a=y/b,ax+by=a^2+b^2
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The given system of equations may be written as
x+y−(a+b)=0
ax−by−(a2−b2)=0
By cross-multiplication, we get
−(a2−b2)−(−b)×−(a+b)x=−(a2−b2)−a×−(a+b)−y=1×−b−a×11
⇒−a2+b2−ab−b2x=−a2+b2+a2+ab−y=−b−a1
⇒−a(a+b)x=b(a+b)−y=−(a+b)1
⇒−a(a+b)x=−b(a+b
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