Question

x√a=y√b=z√c and abc=1 then prove that x+y+z=0.

Answer 1

I think this is the equation we have:
$\sqrt[x]{a} = \sqrt[y]{b} = \sqrt[z]{c}$

We can write this as

$a^{ \frac{1}{x}} = b^{ \frac{1}{y}} = c^{ \frac{1}{z}} = k$
Let these be k
so, we have
$a = k^{x} \\ b = k^{y} \\ c = k^{z}$
And we have
abc = 1
So, substituting values, we get
$k^{x + y + z} = 1$
$k^{x + y + z} = 1^{0}$
So, x + y + z = 0
Hence proved.

Answer 2

Step-by-step explanation:

Hope it helps you......

please mark my answer as brainleist.........