Math, asked by Jeeya06, 11 months ago

[x^a2÷x^b2]^1÷a+b × [x^b2÷x^c2]^1÷b+c × [x^c2÷ x^a2]^1÷c+a

Answers

Answered by Bucchi
2

Step-by-step explanation:

i hope u will understand.......what i want to say

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Answered by palarpit2906
0

Step-by-step explanation:

(x^a2/x^b2) 1/a+b×(x^b2/x^c2) 1/b+c ×(x^c2/x^a2) 1/c+a =1

1/a+b*1/b+c*1/c+a=1

1*1*1=1

1=1

hence proved

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