Question

x-ab/a+b + x-bc/b+c + x-ca/c+a=a+b+c

Answer 1

given =x-ab/a+b + x-bc/b+c + x-ca/c+a=a+b+c

to find: value of x

1. to find the value of x, we need to take all the terms on one side.

• {(x-ab/ a+b)-c} + {(x-bc/b+c) -a} +{(x-ca/c+a) - b} = 0

2. after taking all terms on one side, start the calculations.

• {x-ab-ac-bc/a+b}+{x-bc-ac-ab/b+c}+{x-ac-bc-ab/c+a} = 0

3. now after this, taking x-ab-bc-ac common from all three terms,

• x-ab-bc-ac{(1/a+b) + (1/b+c) + (1/ a+c)}=0

4. now, putting x-ab-bc-ac on lhs and rest terms on den of zero,

•     x-ab-bc-ac=0

x= ab+bc+ac