x=acos^2thetasintheta y=asin^2thetacostheta then find (x^2+y^2)^3by x^2y^2
Answers
Answer:
Given : x=acos
2
θsinθ and y=asin
2
θcosθ
x
2
y
2
(x
2
+y
2
)
3
=
a
4
cos
6
θsin
6
θ
(a
2
cos
4
θsin
2
θ+a
2
cos
2
θsin
4
θ)
3
=
a
4
cos
6
θsin
6
θ
a
6
cos
6
θsin
6
θ(cos
2
θ+sin
2
θ)
3
(∵sin
2
θ+cos
2
θ=1)
=a
2
(1)
3
=a
2
Hence, option C is correct.
Step-by-step explanation:
Step-by-step explanation:
Correct option is
C
a
2
Given : x=acos
2
θsinθ and y=asin
2
θcosθ
x
2
y
2
(x
2
+y
2
)
3
=
a
4
cos
6
θsin
6
θ
(a
2
cos
4
θsin
2
θ+a
2
cos
2
θsin
4
θ)
3
=
a
4
cos
6
θsin
6
θ
a
6
cos
6
θsin
6
θ(cos
2
θ+sin
2
θ)
3
(∵sin
2
θ+cos
2
θ=1)
=a
2
(1)
3
=a
2
Hence, option C is correct.