X = acoso+bsino, y = asino - bcoso then a^2+b^2=?
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Given
X=a cos∅+ b Sin∅
&
Y=a Sin∅-b cos∅
To find
a²+b²
Solution
Both side squaring
X²=(a cos∅+ b Sin∅)²
=>x²=a² cos²∅ + b² Sin²∅ + 2ab cos∅.sin∅__(1)
again both side squaring
Y²=(a Sin∅-b cos∅)²
=>y²=a² sin²∅ + b² cos²∅ - 2ab cos∅.sin∅__(2)
Joining Equation (1) and (2)
=>x² + y²=a² cos²∅ + b² Sin²∅ + 2ab cos∅.sin∅ + a² sin²∅ + b² cos²∅ - 2ab cos∅.sin∅
=>x²+y² = a²cos²∅ + a² sin²∅ + b² sin²∅+ b² cos²∅
=>x²+y²=a²(cos²∅ + sin²∅ )+ b²( sin²∅+ cos²∅)
=>x²+y²=a²+b²
hence,x²+y²=a²+b²
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