Math, asked by norbusonam2233, 11 months ago

X alone can complete a work in 20 days. X is 20% less efficient than Y. In how many days Y alone can do the work.​

Answers

Answered by Naishadh2819
3

Answer:16 days

Step-by-step explanation:

X is 20%less thanY , if it takes 20 days ,then 10%=2days . So,20%=4days. 20-4days=16days

Answered by asahilthakur
3

Answer:

Y alone can do the work in 16 days.

Step-by-step explanation:

X can do the work in 20 days. This means that in 1 day, X can do 1/20th work. X is 20% less efficient than Y. This means that Y is 25% more efficient than X.

Hence, Y's one day work = 1/20 × 125/100 = 1/16

Therefore, Y can do the work in 16 days.

Similar questions