Math, asked by parthsvjoshi, 11 months ago

X alone takes 14 days to build a water tank. Y working alone takes 21 days to build
tank is built by X alone for half the time and the remaining half time by X and Y together then determine
time taken to build the tank.​

Answers

Answered by bhagyashreechowdhury
0

If the tank is built by X alone for half the time and the remaining half time by X and Y together then time taken to build the tank is 10.5 days.

Step-by-step explanation:

Time taken by X alone to build a water tank = 14 days

So, X’s 1-day work = \frac{1}{14}

Time taken by Y alone to build the water tank = 21 days  

So, Y’s 1-day work = \frac{1}{21}

∴ The amount of work done by X & Y together =  [\frac{1}{14} + \frac{1}{21} ]

It is given that X alone does the work for half the time and for the remaining half time the work is done by X & Y together.

Therefore, we can write the eq. as,

= [½ * \frac{1}{14} ] + [½ * {\frac{1}{14} + \frac{1}{21}}]  

= \frac{1}{28} + [½ * {\frac{3+2}{42} }]

= \frac{1}{28} + \frac{5}{84}

= \frac{84+140}{28*84}

= \frac{224}{28*84}

= \frac{2}{21}

= \frac{1}{10.5}

Thus, the time taken to build the water tank is 10.5 days.

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