Question

x & y are two positive integers such that(4x²-3y²):(2x²+3y²)=37:59 what is the value of x:y

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Answer 1

Step-by-step explanation:

1st integer= x

2nd integer=y

Ratio = 37:59

(4x²-3y²):(2x²+3y²)=37:59

4x²-3y²/2x²+3y²=37/59

59(4x²-3y²)=37(2x²+3y²)

236x²-177y²=74x²+111y²

236x²-74x²=111x²+177y²

162x²=288y²

x²/y²=288/162

x²/y²=16/9

x/y=4/3

x:y=4:3