x and x+y are the square of two consecutive natural number. what is the square of the natural number.
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let the two consecutive natural no is m, m+1
where m=1,2,3,4,5,....
so m^2=x.... (1)
(m+1)^2=x+y...... (2)
or m^2+2m+1=x+y=m^2+y
or 2m+1=y
and x=m^2 (given)
by this process u can solve
where m=1,2,3,4,5,....
so m^2=x.... (1)
(m+1)^2=x+y...... (2)
or m^2+2m+1=x+y=m^2+y
or 2m+1=y
and x=m^2 (given)
by this process u can solve
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0
Answer:
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