Question

x and y are real numbers such that xy=x+y=x/y (xis not =0 y is not =0) .Then find the numerical value of(x-y) plzz tell me answer with process

Answer 1

xy = x/y 
===> xy^2 = x 
===> y^2 = 1 ... (division by x is valid, since x is non-zero) 
===> y = -1 or 1 

If y = 1, then from xy = x + y, we have: 

y = y + 1 
0 = 1 

which is a contradiction, so y cannot equal 1. Thus y = -1, and so: 

xy = x + y 
===> -x = x - 1 
===> 2x = 1 
===> x = 1/2 

So, the only solution is x = 1/2, y = -1 (which is indeed a solution), and so: 

x - y = 1/2 - -1 = 3/2

hope this is helpful to you

Answer 2

Answer:

3/2 or 1.5

as x=0.5 and y=-1.0;

and x-(-y)=0.5+1=1.5;