Question

X and Y are two stations 600 km apart. At 7 a.m. on a certain day, train P starts from X and moves towards Y at

90 km/hr. At 8:20 am. train Q starts from Y and moves towards X at 150 km/hr. Find the distance between their

meeting point and station X.
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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Given :-

◾Total Distance => 600 km

◾Speed of Q =>150km/h

◾Speed of P => 90 km/h

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To Find :-

◾Meeting point between Q and P.

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Solution:-

◾Let Q travels M km to meet P.

◾P need to travel = (600 - M) km.

◾Time taken by Q to reach meeting point = Time taken by P to reach same place.

${\LARGE{\rm{\frac{M}{150}= \frac{(600 -M)}{90}}}}$

$: {\implies {\rm{90M = 150 \times 600 - 150M}}}$

$:{\implies {\rm{90M + 150M = 150 \times 600}}}$

$:{\implies{\rm{240M = 150 \times 600}}}$

$</strong><strong>{</strong><strong>\</strong><strong>p</strong><strong>i</strong><strong>n</strong><strong>k</strong><strong>{\boxed</strong><strong>{</strong><strong>:{\implies{\rm{\rm{M = 375km}}}</strong><strong>}</strong><strong>}</strong><strong>}</strong><strong>}</strong><strong>$

So, Q travels 375 km and P travels (600 - 375) = 225km to meet.

Thus, Q travels = 375-225= 150km more than P.

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