Question

X and Y both a moving particle the uncertainty in measure of momentum of Y is half then that of x if the uncertainty of positive of X is plus or minus 0.05 Armstrong than that of y

Answer 1

Answer:

0.025 bcz.its given that Y is half of X so simple ...

Answer 2

The uncertainty in measure of momentum of Y is $1 \times 10^{-9} cm$

Explanation:

Given,

Uncertainty of positive of X = $0.05 \AA$

$\Delta p$ $of$ $y = \frac{1}{2}$  $of$ $x = \frac{1}{2}$ $\Delta p_x$

For x $\Delta x \Delta p = \frac{h}{4\pi }$

$0.05 \AA \times \Delta p_x = \frac{h}{4\pi }$

∴$\Delta x = 0.05 \times 2$

$\Delta x = 0.1 \times 10^{-10}$

$\Delta x = 1 \times 10^{-9}$

Hence, the uncertainty in measure of momentum of Y is $1 \times 10^{-9} cm$.

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