X and y can construct a small quarantine center in 12 days , which x alone can construct in30 days. in how long y alone can construct it
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Given :-
- (x + y) can construct a small quarantine center = in 12 days .
- x alone can construct in 30 days.
To Find :-
- in how long y alone can construct it ?
Solution :-
LCM of 12 and 30 = 60 units = Let Total work .
Than,
→ Efficiency of (x + y) = (Total work) / (Total No. of Days by both) = 60/12 = 5 units / Day.
→ Efficiency of x alone = (Total work) / (Total No. of Days by x alone) = 60/30 = 2 units / Day.
As, we can see efficiency of (x + y) is 5units / day and efficiency of x alone is 2 units/day .
Therefore,
→ Efficiency of y alone = (x + y) - x
→ Efficiency of y alone = 5 - 2 = 3 units / Day.
Hence,
→ Time taken by y alone to complete Total work alone = (Total work) / (Efficiency of y alone) = 60/3 = 20 Days. (Ans.)
∴ y alone can construct the small quarantine center alone in 20 days.
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