Math, asked by anshulsharma8863, 9 months ago

X and Y can do a piece of work in 10 days and 6 days respectively they work together for 2 days and Y leaves the work. In how many days X will finish the remaining work?

Answers

Answered by Anonymous
51

X and Y do a piece of work in 10 days and 6 days.

So,

\sf{Work \:done \:by \:X\: in \:one\: day\: =\: {\frac{1}{10}}}

And

\sf{Work \:done \:by \:Y\: in \:one\: day\: =\: {\frac{1}{6}}}

Now,

\sf{Work\:done\:by\:both\:X\:and\:Y\:in\:one\:day}

\implies\:\sf{\frac{1}{10}\:+\:\frac{1}{6}}

\implies\:\sf{\frac{3\:+\:5}{30}}

\implies\:\sf{\frac{8}{30}}

\implies\:\sf{\frac{4}{15}}

Both X and Y work together for 2 days.

So,

\sf{Work\:done\:by\:X\:and\:Y\:in\:2\:days}

\implies\:\sf{\frac{4}{15}\:\times\:2}

\implies \:\sf{\frac{8}{15}}

\sf{Remaining \:work\:=\:1\:-\:\frac{8}{15}}

\implies\:\sf{\frac{7}{15}}

We have to find that in how many days X will complete the remaining work.

From above calculations we find that Remaining work is 7/15 and X do a piece of work in 10 days.

So,

\bold{\underline{\sf {Time\:taken\:by\:X\:to\:complete \:the\:remaining }}}\bold{\underline{\sf {work}}}

\implies \:\sf{\frac{7}{15}\:\times\:10}

\implies \:\sf{\frac{14}{3}}

X complete the remaining work in 14/3 days.

Answered by lAravindReddyl
54

Answer:-

\bold{\: \dfrac{14}{13} } \: days

Explanation:-

Given:-

  • x can do a piece of work in 10 days
  • y can do a piece of work in 6 days
  • Both x and y work together for 2 days and y leaves the work

To Find:-

The time taken by X to finish the work

Solution:-

Work done by X in one day = \dfrac{1}{10}

Work done by Y in one day= \dfrac{1}{6}

Given, both X and Y work together for 2 days

work done by X in 2 days = 2 \times \dfrac{1}{10} = \dfrac{1}{5}

Work done by Y in 2 days = 2 \times \dfrac{1}{6} = \dfrac{1}{3}

Work done by both X and Y in two days

{\rightarrow} \: \dfrac{1}{5}+ \dfrac{1}{3}

{\rightarrow} \: \dfrac{3+5}{15}

{\rightarrow} \: \dfrac{8}{15}

Now, Y leaves the work

Work remaining :-

{\rightarrow} \: 1 - \dfrac{8}{15}

{\rightarrow} \: \dfrac{15 - 8}{15}

{\rightarrow} \: \dfrac{7}{15}

Time taken by X to do the remaining work

{\rightarrow} \: \dfrac{\frac{7}{15}}{10}

{\rightarrow} \: \dfrac{7}{15} \times 10

 \bold{{\rightarrow} \: \dfrac{14}{13} } \: days

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