Question

X and y can do a piece of work in 20 days and 12 days respectively.X started the work alone and then after 4 days y joined him till the work completion. How long did the work last

Answer 1

I hope it's help u...............

Answer 2

The work lasts for 6 days

Step-by-step explanation:

X can complete work in days = 20

X 's 1 day work = $\frac{1}{20}$

Y can complete work in days = 12

Y's 1 day work = $\frac{1}{12}$

(X+Y)'s 1 day work =  $\frac{1}{20}+\frac{1}{12}=\frac{2}{15}$

X 's 4 days work =$\frac{4}{20}$

Remaining work =$1 - \frac{4}{20}=\frac{16}{20}$

(X+Y) can complete work together in days =$\frac{15}{2}$

(X+Y) can complete 16/ 20 work together in days =$\frac{15}{2} \times \frac{16}{20}=6$

The work lasts for 6 days

#Learn more:

A can do a piece of work in 34 days while B can do it in 46 days.A and B started the work and A left after working till 11 days.then B continued the work.after working for 6 days C joined B.C is twice plus 30% efficient than B.they worked for 4 days until completion of work and C leaves.how many days was the work completed?

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