Question

X and y coordinate system of potential at a poont p(x,y) is given by v=axy ; where a is a constant, if r is the distance of point p from origin then electric field at p is proportional to?

Answer 1

Answer:

As we learned

 

Relation between field and potential -

E=\frac{-dv}{dr}

- wherein

\frac{dv}{dr} -   Potential gradient.

 

 

By using   E=-\frac{dV}{dr}            E_{x}=-\frac{dV}{dx}=-ay,        E_{y}=-\frac{dV}{dy}=-ax,

Electric field at point P E=\sqrt{E_{x}^{2}+E_{y}^{2}}=a\sqrt{x^{2}+y^{2}}=ar i.e., Eµr

 

Option 1)

r

 

 

 

Option 2)

r^{-1}

Option 3)

r^{-2}

Option 4)

r^{2}

Step-by-step explanation: