Question

X and Y coordinates of a particle varies with time as x=2t2 and Y=3t. Find out magnitude of velocity and acceleration at t=1 second​

Answer 1

Answer:

-4m/s2

Explanation:

x=5t−2t2

y=10t

dtdx=5−4t

ax=dt2d2x=−4

ay=dt2d2y=0

a=ax+ay=−4+0

a=−4 ms2

Answer 2

Magnitude of acceleration= 4m/s

Magnitude of velocity= 5m/s

Explanation:

dx/dt = v = 4t

dx/dt= v = 3

dv/dt = a = 4

dv/dt = a = 0

therefore acceleration = (4² + 0²)½

here acceleration is constant. it does not change with time

and at t=1

v= (4²+3²)½

=25½

=5m/s