Question

. X and Y start moving towards each other
from two places 200 m apart. After walking
60 m, Y turns left and goes 20 m, then he
turns right and goes 40 m. He then turns
right again and comes back to the road on
which he had started walking. If X and Y
walk with the same speed, what is the
distance between them now?
(a) 20 m (b) 30 m (c) 40 m (d) 50 m​

Answer 1

ANSWER :-

The distance between X and Y is ( c) 40 m....

explanation :-

▪ we can see in the attached figure that X finally covers the distance of

= ( 60m + 20m + 40m + 20m )

= 140 m

since, it's given in the question that both, X and Y are walking at the same speed .so, the distance covered by both of them at an instance would be same...

thus, distance covered by Y = 140m

but as we can see in the figure that X was not walking at the straight path between X and Y

therefore, he (X) covers 100m of the road from where he initially started while Y covers 140m .

both have started from opposite direction

the distance between them , now = 140m - 100m

= 40m