Question

X and Y together do a certain piece of work in 8 days. if X does it alone complete the work in 12 days. in how many days will Y alone complete the work ?​

Answer 1

$\textbf{\huge{ANSWER:}}$

$\sf{Given\:is\:that:}$

X and Y can do the work together in - 8 days

X can do the work alone in - 12 days

$\sf{To\:find:}$

Y can do the work alone in ?

$\sf{The\:Solution:}$

One day work of X and Y together - $\frac{1}{8}$

One day work of X - $\frac{1}{12}$

One day work of Y = $\tt{One\:day\: work\: of \:X \:and \:Y \:together - One\:day\:work\:of\:X\:alone}$

=》 $\tt{\frac{1}{8} - \frac{1}{12}}$

=》 $\tt{\frac{3-2}{24}}$

=》 $\tt{\frac{1}{24}}$

One day work = $\frac{1}{24}$

Total days taken by Y to complete work = $\tt{24\:days}$

Answer 2

$\huge\textbf{Answer}$


X and Y together do a certain piece of work in 8 days.

Work done by both (X and Y) in 1 day = $\dfrac{1}{8}$ days

If X along complete the work in 12 days.

Then work done by X in 1 day = $\dfrac{1}{12}$ days.

Now we have to find the work done by Y alone.

Work done by XY = Work done by X + Work done by Y

Work done by Y = Work done by XY - Work done by X

Work done by Y = $\dfrac{1}{8}$ - $\dfrac{1}{12}$

= $\dfrac{3\:-\:2}{24}$

= $\dfrac{1}{24}$ days


$\textbf{Work done by Y alone is 24 days.}$