X andY are the midpoints of sides AB and AC of a triangle ABC. if BC+XY=12units then BC-XY=?
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It's based on similarity of triangles
Since it's given that X and Y are mid points of AB and AC respectively
By mid point theorem
XY =1/2BC
LET BC = a
Then XY =a/2
Given
XY +BC =12
=> a+a/2=12
=>3a/2=12
=>3a=24
=>a=24/3
=>a=8
Now BC-XY
=a-a/2
=8-8/2
=8-4
=4
Hence BC-XY=4 Answer
Since it's given that X and Y are mid points of AB and AC respectively
By mid point theorem
XY =1/2BC
LET BC = a
Then XY =a/2
Given
XY +BC =12
=> a+a/2=12
=>3a/2=12
=>3a=24
=>a=24/3
=>a=8
Now BC-XY
=a-a/2
=8-8/2
=8-4
=4
Hence BC-XY=4 Answer
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