x approaches to 1 from right hand side find 5x^2-5/|x-1|
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Answer:
Left hand limit:
x→1
lt
f(x)
=
x→1
lt
1+x
2
[∵f(x)=1+x
2
when x≤1]
=1+1
=2
Right hand limit
x→1
+
lt
f(x)
=
x→1
lt
2−x [∵f(x)=2−x when x>1]
=1
Since,
x→1
−
lt
f(x)
=
x→1
+
lt
f(x),
x→1
lt
f(x) does not exist
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