Question

X articles are bought at (X - 8) rupees each and (x -2 ) some other articles are bought at rupees (x-3) each .if the total cost of all these articles is 76 rupees how many articles of first kind where bought?

Answer 1

Answer: There are 10 articles of first kind that were bought.

Step-by-step explanation:

Since we have given that

Number of articles = x

Cost of each of these articles = (x-8)

Number of articles = (x-2)

Cost of each of these articles = (x-3)

Total cost of all these articles = Rs. 76

According to question,

$x(x-8)+(x-2)(x-3)=76\\\\x^2-8x+x^2-3x-2x+6=76\\\\2x^2-8x-5x+6=76\\\\2x^2-13x=76-6\\\\2x^2-13x=70\\\\2x^2-13x-70=0\\\\2x^2-20x+7x-70=0\\\\2x(x-10)+7(x-10)=0\\\\(2x+7)(x-10)=0\\\\x=\frac{-7}{2},10$

Hence, there are 10 articles of first kind that were bought.