Question

X-axis.
=0
4.
A(5,- 4) and B(7,6) are two points. If a point 'P' moves such that PA : PB = 2:3, then find the locus
of 'P'.
0​

Answer 1

Answer:

Given,

A(4,0),B(−4,0)

Let P(x,y)

∣PA−PB∣=6

(x−4)

2

+y

2

−

(x+4)

2

+y

2

=6

(x−4)

2

+y

2

=6+

(x+4)

2

+y

2

squaring on both sides, we get,

(x−4)

2

+y

2

=36+(x+4)

2

+y

2

+12

(x+4)

2

+y

2

−16x−36=12

(x+4)

2

+y

2

−4(4x+9)=12

(x+4)

2

+y

2

16x

2

+81+72x=9[(x+4)

2

+y

2

]

7x

2

−9y

2

=63

Answer 2

So,hence the answer is 5x^2+5y^2-34x+120y+29

=0.